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(H)=-6H^2+384
We move all terms to the left:
(H)-(-6H^2+384)=0
We get rid of parentheses
6H^2+H-384=0
a = 6; b = 1; c = -384;
Δ = b2-4ac
Δ = 12-4·6·(-384)
Δ = 9217
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{9217}}{2*6}=\frac{-1-\sqrt{9217}}{12} $$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{9217}}{2*6}=\frac{-1+\sqrt{9217}}{12} $
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